Benicio Del Toro Going Undercover in 'Making Jack Falcone'
Even though The Wolfman turned out to be a tragic disappointment, not much blame, if any, can be placed on Benicio Del Toro, who turned in a decent performance. Now Del Toro's moving to a more recent past as Deadline reports he has signed on to portray real-life FBI undercover agent Jack (or Joaquin) Garcia in the crime drama Making Jack Falcone focusing on the agents exploits in taking down no less than 39 members of New York's Gambino crime family. Crime stories are a dime a dozen, so what do Del Toro and producers Steven Soderbergh and Peter Buchman (Che) find so interesting about this one? Read on!
Unlike the focus of countless other undercover police dramas highlighting the dilemma of loyalty and the stress of pretending to be just one fake criminal, Garcia had the difficult task of keeping several undercover identities straight. He would go from the New York case to Miami, where he posed as a New York capo in a sting against crooked cops, to Atlantic City, where he pretended to be a drug dealer in another case. Garcia's undercover tactics under the alias of Jack Falcone were so convincing, that despite his Cuban ethnicity, he had the mob so convinced that he was Italian that he was about to be "made" before the FBI stepped in.
This makes another in a series of interesting role choices for Del Toro who also has a completely surprising and unexpected comedic turn in the works as Moe in the Farrelly Brothers long-gestating Three Stooges film. However, this role might prove a challenge for him physically since Garcia, ironically enough, didn't have the most conspicuous frame coming in at 6'4" and 390 pounds. That'd probably be quite an unsafe amount of weight to gain so I'm sure there will be some make-up involved, but who knows. Either way, I'm always up for an intense crime drama and this one is no exception. However, we'll have to wait and see how soon this one gets off the ground, especially if Three Stooges is coming first, so stay tuned as things develop.